25 Oct 2017

neco gce 2017 physics practical answers now posted

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1ai – 1aiii)
i: 1, 2, 3, 4, 5, 6
Y(cm): 20.00, 17.40, 15.20, 12.60, 10.40
Z(cm): 17.40, 15.20, 13.40, 11.20, 9.40
P= y-z(cm): 2.60, 2.20, 1.80, 1.40, 1.00



(1av)
Slope = Δmx/Δmp
Where (Δ means change)
S= 30-10cm/
2.60-1cm
S = 20/1.60
S = 12.50

(1avi)
U = 100/s
= 100/12.50
= 8

(1avii)
(i) I will avoid error due to parallax while reading the metre rule
(ii) I will ensure the mass is kept dried before weighing

(1bi)
Weight in air = 10/1000
= 0.01kg
Weight in water = 9.75kg
9.75/9.75-0.01
= 9.75/9.74 = 1.00
Density of solid = 1/1000 = 0.001g/cm-³

(1bii)
It is because the molecules of the particles is packed together and no space for air interference while solid pieces of iron has volatile or irregular pattern which allows air interference

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(3ai – 3aii)
TABULATE :
Readings: 1,2,3,4,5
R(n): 1.00,2.00,3.00,4.00,5.00
R^-1(n^-1): 1.000,0.500,0.333,0.250,0.200
l(cm): 13.50,27.50,41.50,55.00,69.50
l^-1(cm^-1): 0.074,0.036,0.024,0.018,0.014

(3av)
Slope=Change in R^-1/Change in L^-1
=(0.500-0.200)/(0.036-0.018)
S=0.30/0.018
=16.67cm/n

(3avi)
Rs=100/16.67
Rs=5.99880n/cm
Rs=6.0n/cm

(3avii)
-I must be ensured of accurate readings thrrough my resistance box
-I must be ensured of tight connections throughout my experiments



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2bi) I Rainbow
II Wave length

2v)
​SLOPE​

Slope,s =y2-y1/x2-x1
=56.7-20/4-1
=36.7/3
=12.233
=12.23

2vi)

U = 100/S = 100/12.23
= 8.176
=8.18

2vii)

– I will avoid error due to parallax while reading the meter rule.

-I will ensure the mass is kept dried before weighing

2aiv)
-I ensured tight connections
-I avoided error due to parallax when reading the voltmetre
-I ensured the key is opened after each reading to prevent the cell from running down



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